2176. Count Equal and Divisible Pairs in an Array
Given a 0-indexed integer array
numsof lengthnand an integerk, return the number of pairs(i, j)where0 <= i < j < n, such thatnums[i] == nums[j]and(i * j)is divisible byk.Example 1:
Input: nums = [3,1,2,2,2,1,3], k = 2
Output: 4
Explanation:
There are 4 pairs that meet all the requirements:
- nums[0] == nums[6], and 0 * 6 == 0, which is divisible by 2.
- nums[2] == nums[3], and 2 * 3 == 6, which is divisible by 2.
- nums[2] == nums[4], and 2 * 4 == 8, which is divisible by 2.
- nums[3] == nums[4], and 3 * 4 == 12, which is divisible by 2.
Example 2:
Input: nums = [1,2,3,4], k = 1
Output: 0
Explanation: Since no value in nums is repeated, there are no pairs (i,j) that meet all the requirements.
def countPairs(self, nums: List[int], k: int) -> int:
pos = defaultdict(list)
count = 0
for i, num in enumerate(nums):
for j in pos[num]:
if (i * j) % k == 0:
count += 1
pos[num].append(i)
return count