485. Max Consecutive Ones

Given a binary array nums, return the maximum number of consecutive 1's in the array.

Example 1:

Input: nums = [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.

Example 2:

Input: nums = [1,0,1,1,0,1]
Output: 2

def findMaxConsecutiveOnes(self, nums: List[int]) -> int:
	ma = 0
	count = 0
	for i in nums:
		if i == 1:
			count+=1
		else:
			count =0
		ma = max(ma, count)
	return ma